16c^(1/3)-24c=0

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Solution for 16c^(1/3)-24c=0 equation:


c in (-oo:+oo)

16*c^(1/3)-(24*c) = 0

16*c^(1/3)-24*c = 0

t_1 = c^(1/3)

16*t_1^1-24*t_1^3 = 0

16*t_1-24*t_1^3 = 0

8*t_1*(2-3*t_1^2) = 0

-3*t_1^2 = -2 // : -3

t_1^2 = 2/3

t_1^2 = 2/3 // ^ 1/2

abs(t_1) = (2/3)^(1/2)

t_1 = (2/3)^(1/2) or t_1 = -(2/3)^(1/2)

8*t_1 = 0

8*t_1 = 0 // : 8

t_1 = 0

t_1 = (2/3)^(1/2)

c^(1/3)-(2/3)^(1/2) = 0

1*c^(1/3) = (2/3)^(1/2) // : 1

c^(1/3) = (2/3)^(1/2)

c^(1/3) = (2/3)^(1/2) // ^ 3

c = (2/3)^(3/2)

t_1 = -(2/3)^(1/2)

c^(1/3)+(2/3)^(1/2) = 0

1*c^(1/3) = -(2/3)^(1/2) // : 1

c^(1/3) = -(2/3)^(1/2)

( -(2/3)^(1/2) < 0 i 1/3 in (0:1) ) => c należy do O

t_1 = 0

c^(1/3)+0 = 0

c^(1/3) = 0

1*c^(1/3) = 0 // : 1

c^(1/3) = 0

c = 0

c in { (2/3)^(3/2), 0 }

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